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Forum Posts
Tang Derek
Apr 06, 2021
In Euclid Math Contest
Suppose that the function g satisfies g(x) = 2x − 4 for all real numbers x and that g −1 is the inverse function of g. Suppose that the function f satisfies g(f(g −1 (x))) = 2x 2 + 16x + 26 for all real numbers x. What is the value of f(π)? I got to this step: f ((x + 4)/2) = (x + 4)^2 − 1 In answer key it says Thus, we can replace (x + 4)/2 with π, which is equivalent to replacing x + 4 with 2π why can we replace x+4 with 2π?
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Tang Derek
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